40=-0.02x^2+1.12x

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Solution for 40=-0.02x^2+1.12x equation: 



40=-0.02x^2+1.12x

We move all terms to the left:

40-(-0.02x^2+1.12x)=0

We get rid of parentheses

0.02x^2-1.12x+40=0

a = 0.02; b = -1.12; c = +40;
Δ = b2-4ac
Δ = -1.122-4·0.02·40
Δ = -1.9456
Delta is less than zero, so there is no solution for the equation

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